0.25=x(1-x)

Solution for 0.25=x(1-x) equation:

0.25=x(1-x)

We move all terms to the left:

0.25-(x(1-x))=0

We add all the numbers together, and all the variables

-(x(-1x+1))+0.25=0


We calculate terms in parentheses: -(x(-1x+1)), so:

x(-1x+1)

We multiply parentheses

-1x^2+x

Back to the equation:

-(-1x^2+x)


We get rid of parentheses

1x^2-x+0.25=0

We add all the numbers together, and all the variables

x^2-1x+0.25=0

a = 1; b = -1; c = +0.25;
Δ = b2-4ac
Δ = -12-4·1·0.25
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{1}{2}=1/2$