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0.25x(6x+1)=x+1.25
We move all terms to the left:
0.25x(6x+1)-(x+1.25)=0
We multiply parentheses
0x^2+0x-(x+1.25)=0
We get rid of parentheses
0x^2+0x-x-1.25=0
We add all the numbers together, and all the variables
x^2-1.25=0
a = 1; b = 0; c = -1.25;
Δ = b2-4ac
Δ = 02-4·1·(-1.25)
Δ = 5
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{5}}{2*1}=\frac{0-\sqrt{5}}{2} =-\frac{\sqrt{}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{5}}{2*1}=\frac{0+\sqrt{5}}{2} =\frac{\sqrt{}}{2} $
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