0.25x+0.05(3x)+0.1(x+4)+1(x)=7.50

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Solution for 0.25x+0.05(3x)+0.1(x+4)+1(x)=7.50 equation:



0.25x+0.05(3x)+0.1(x+4)+1(x)=7.50
We move all terms to the left:
0.25x+0.05(3x)+0.1(x+4)+1(x)-(7.50)=0
We add all the numbers together, and all the variables
0.25x+0.053x+0.1(x+4)+1x-(7.5)=0
We add all the numbers together, and all the variables
1.303x+0.1(x+4)-7.5=0
We multiply parentheses
1.303x+0.1x+0.4-7.5=0
We add all the numbers together, and all the variables
1.403x-7.1=0
We move all terms containing x to the left, all other terms to the right
1.403x=7.1
x=7.1/1.403
x=5+0.084999999999999/1.403

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