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0.25x+3/8x=5
We move all terms to the left:
0.25x+3/8x-(5)=0
Domain of the equation: 8x!=0We multiply all the terms by the denominator
x!=0/8
x!=0
x∈R
(0.25x)*8x-5*8x+3=0
We add all the numbers together, and all the variables
(+0.25x)*8x-5*8x+3=0
We multiply parentheses
0x^2-5*8x+3=0
Wy multiply elements
0x^2-40x+3=0
We add all the numbers together, and all the variables
x^2-40x+3=0
a = 1; b = -40; c = +3;
Δ = b2-4ac
Δ = -402-4·1·3
Δ = 1588
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1588}=\sqrt{4*397}=\sqrt{4}*\sqrt{397}=2\sqrt{397}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-2\sqrt{397}}{2*1}=\frac{40-2\sqrt{397}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+2\sqrt{397}}{2*1}=\frac{40+2\sqrt{397}}{2} $
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