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0.25x^2-1=0
a = 0.25; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·0.25·(-1)
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-1}{2*0.25}=\frac{-1}{0.5} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+1}{2*0.25}=\frac{1}{0.5} =2 $
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