0.2X2+0.4x=0.6

Solution for 0.2X2+0.4x=0.6 equation:

0.2X^2+0.4X=0.6

We move all terms to the left:

0.2X^2+0.4X-(0.6)=0

We add all the numbers together, and all the variables

0.2X^2+0.4X-0.6=0

a = 0.2; b = 0.4; c = -0.6;
Δ = b2-4ac
Δ = 0.42-4·0.2·(-0.6)
Δ = 0.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.4)-\sqrt{0.64}}{2*0.2}=\frac{-0.4-\sqrt{0.64}}{0.4}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.4)+\sqrt{0.64}}{2*0.2}=\frac{-0.4+\sqrt{0.64}}{0.4}
$