0.2x2+90x+-2000=0

Solution for 0.2x2+90x+-2000=0 equation:

0.2x^2+90x+-2000=0

We add all the numbers together, and all the variables

0.2x^2+90x=0

a = 0.2; b = 90; c = 0;
Δ = b2-4ac
Δ = 902-4·0.2·0
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8100}=90$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(90)-90}{2*0.2}=\frac{-180}{0.4}
=-450
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(90)+90}{2*0.2}=\frac{0}{0.4}
=0
$