0.2y+0.8(10-y)=5

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Solution for 0.2y+0.8(10-y)=5 equation:



0.2y+0.8(10-y)=5
We move all terms to the left:
0.2y+0.8(10-y)-(5)=0
We add all the numbers together, and all the variables
0.2y+0.8(-1y+10)-5=0
We multiply parentheses
0.2y-0.8y+8-5=0
We add all the numbers together, and all the variables
-0.6y+3=0
We move all terms containing y to the left, all other terms to the right
-0.6y=-3
y=-3/-0.6
y=+5

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