0.3(2x+3)+1.1=-0.2(x-3)-0.8

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Solution for 0.3(2x+3)+1.1=-0.2(x-3)-0.8 equation: 



0.3(2x+3)+1.1=-0.2(x-3)-0.8

We move all terms to the left:

0.3(2x+3)+1.1-(-0.2(x-3)-0.8)=0

We multiply parentheses

0.6x-(-0.2(x-3)-0.8)+0.9+1.1=0



We calculate terms in parentheses: -(-0.2(x-3)-0.8), so:

-0.2(x-3)-0.8

We multiply parentheses

-0.2x+0.6-0.8

We add all the numbers together, and all the variables

-0.2x-0.2

Back to the equation:

-(-0.2x-0.2)



We add all the numbers together, and all the variables

0.6x-(-0.2x-0.2)+2=0

We get rid of parentheses

0.6x+0.2x+0.2+2=0

We add all the numbers together, and all the variables

0.8x+2.2=0

We move all terms containing x to the left, all other terms to the right

0.8x=-2.2

x=-2.2/0.8

x=-2+0.6/0.8

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