0.3(2x+3)+1.1=-0.2(x-3)-18

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Solution for 0.3(2x+3)+1.1=-0.2(x-3)-18 equation:



0.3(2x+3)+1.1=-0.2(x-3)-18
We move all terms to the left:
0.3(2x+3)+1.1-(-0.2(x-3)-18)=0
We multiply parentheses
0.6x-(-0.2(x-3)-18)+0.9+1.1=0
We calculate terms in parentheses: -(-0.2(x-3)-18), so:
-0.2(x-3)-18
We multiply parentheses
-0.2x+0.6-18
We add all the numbers together, and all the variables
-0.2x-17.4
Back to the equation:
-(-0.2x-17.4)
We add all the numbers together, and all the variables
0.6x-(-0.2x-17.4)+2=0
We get rid of parentheses
0.6x+0.2x+17.4+2=0
We add all the numbers together, and all the variables
0.8x+19.4=0
We move all terms containing x to the left, all other terms to the right
0.8x=-19.4
x=-19.4/0.8
x=-24+0.2/0.8

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