0.3(2x+3)+1.1=-0.2(x-3)-18

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Solution for 0.3(2x+3)+1.1=-0.2(x-3)-18 equation: 



0.3(2x+3)+1.1=-0.2(x-3)-18

We move all terms to the left:

0.3(2x+3)+1.1-(-0.2(x-3)-18)=0

We multiply parentheses

0.6x-(-0.2(x-3)-18)+0.9+1.1=0



We calculate terms in parentheses: -(-0.2(x-3)-18), so:

-0.2(x-3)-18

We multiply parentheses

-0.2x+0.6-18

We add all the numbers together, and all the variables

-0.2x-17.4

Back to the equation:

-(-0.2x-17.4)



We add all the numbers together, and all the variables

0.6x-(-0.2x-17.4)+2=0

We get rid of parentheses

0.6x+0.2x+17.4+2=0

We add all the numbers together, and all the variables

0.8x+19.4=0

We move all terms containing x to the left, all other terms to the right

0.8x=-19.4

x=-19.4/0.8

x=-24+0.2/0.8

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