0.3(3y-1)=5+0.2y

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Solution for 0.3(3y-1)=5+0.2y equation: 



0.3(3y-1)=5+0.2y

We move all terms to the left:

0.3(3y-1)-(5+0.2y)=0

We add all the numbers together, and all the variables

0.3(3y-1)-(0.2y+5)=0

We multiply parentheses

0.9y-(0.2y+5)-0.3=0

We get rid of parentheses

0.9y-0.2y-5-0.3=0

We add all the numbers together, and all the variables

0.7y-5.3=0

We move all terms containing y to the left, all other terms to the right

0.7y=5.3

y=5.3/0.7

y=7+0.4/0.7

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