0.3(4+2c)=0.1(c+2)

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Solution for 0.3(4+2c)=0.1(c+2) equation: 


Simplifying
0.3(4 + 2c) = 0.1(c + 2)
(4 * 0.3 + 2c * 0.3) = 0.1(c + 2)
(1.2 + 0.6c) = 0.1(c + 2)

Reorder the terms:
1.2 + 0.6c = 0.1(2 + c)
1.2 + 0.6c = (2 * 0.1 + c * 0.1)
1.2 + 0.6c = (0.2 + 0.1c)

Solving
1.2 + 0.6c = 0.2 + 0.1c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-0.1c' to each side of the equation.
1.2 + 0.6c + -0.1c = 0.2 + 0.1c + -0.1c

Combine like terms: 0.6c + -0.1c = 0.5c
1.2 + 0.5c = 0.2 + 0.1c + -0.1c

Combine like terms: 0.1c + -0.1c = 0.0
1.2 + 0.5c = 0.2 + 0.0
1.2 + 0.5c = 0.2

Add '-1.2' to each side of the equation.
1.2 + -1.2 + 0.5c = 0.2 + -1.2

Combine like terms: 1.2 + -1.2 = 0.0
0.0 + 0.5c = 0.2 + -1.2
0.5c = 0.2 + -1.2

Combine like terms: 0.2 + -1.2 = -1
0.5c = -1

Divide each side by '0.5'.
c = -2

Simplifying
c = -2

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