0.3(n-5)=0.4-0.29(n-7)=

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Solution for 0.3(n-5)=0.4-0.29(n-7)= equation: 



0.3(n-5)=0.4-0.29(n-7)=

We move all terms to the left:

0.3(n-5)-(0.4-0.29(n-7))=0

We multiply parentheses

0.3n-(0.4-0.29(n-7))-1.5=0



We calculate terms in parentheses: -(0.4-0.29(n-7)), so:

0.4-0.29(n-7)

determiningTheFunctionDomain
-0.29(n-7)+0.4

We multiply parentheses

-0.29n+2.03+0.4

We add all the numbers together, and all the variables

-0.29n+2.43

Back to the equation:

-(-0.29n+2.43)



We get rid of parentheses

0.3n+0.29n-2.43-1.5=0

We add all the numbers together, and all the variables

0.59n-3.93=0

We move all terms containing n to the left, all other terms to the right

0.59n=3.93

n=3.93/0.59

n=6+0.39/0.59

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