0.3(r+2)=.1(-2r-4)

Solution for 0.3(r+2)=.1(-2r-4) equation:

Simplifying
0.3(r + 2) = 0.1(-2r + -4)

Reorder the terms:
0.3(2 + r) = 0.1(-2r + -4)
(2 * 0.3 + r * 0.3) = 0.1(-2r + -4)
(0.6 + 0.3r) = 0.1(-2r + -4)

Reorder the terms:
0.6 + 0.3r = 0.1(-4 + -2r)
0.6 + 0.3r = (-4 * 0.1 + -2r * 0.1)
0.6 + 0.3r = (-0.4 + -0.2r)

Solving
0.6 + 0.3r = -0.4 + -0.2r

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '0.2r' to each side of the equation.
0.6 + 0.3r + 0.2r = -0.4 + -0.2r + 0.2r

Combine like terms: 0.3r + 0.2r = 0.5r
0.6 + 0.5r = -0.4 + -0.2r + 0.2r

Combine like terms: -0.2r + 0.2r = 0.0
0.6 + 0.5r = -0.4 + 0.0
0.6 + 0.5r = -0.4

Add '-0.6' to each side of the equation.
0.6 + -0.6 + 0.5r = -0.4 + -0.6

Combine like terms: 0.6 + -0.6 = 0.0
0.0 + 0.5r = -0.4 + -0.6
0.5r = -0.4 + -0.6

Combine like terms: -0.4 + -0.6 = -1
0.5r = -1

Divide each side by '0.5'.
r = -2

Simplifying
r = -2