0.3(y+1)-0.4(3-2y)=0.2

Solution for 0.3(y+1)-0.4(3-2y)=0.2 equation:

Simplifying
0.3(y + 1) + -0.4(3 + -2y) = 0.2

Reorder the terms:
0.3(1 + y) + -0.4(3 + -2y) = 0.2
(1 * 0.3 + y * 0.3) + -0.4(3 + -2y) = 0.2
(0.3 + 0.3y) + -0.4(3 + -2y) = 0.2
0.3 + 0.3y + (3 * -0.4 + -2y * -0.4) = 0.2
0.3 + 0.3y + (-1.2 + 0.8y) = 0.2

Reorder the terms:
0.3 + -1.2 + 0.3y + 0.8y = 0.2

Combine like terms: 0.3 + -1.2 = -0.9
-0.9 + 0.3y + 0.8y = 0.2

Combine like terms: 0.3y + 0.8y = 1.1y
-0.9 + 1.1y = 0.2

Solving
-0.9 + 1.1y = 0.2

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '0.9' to each side of the equation.
-0.9 + 0.9 + 1.1y = 0.2 + 0.9

Combine like terms: -0.9 + 0.9 = 0.0
0.0 + 1.1y = 0.2 + 0.9
1.1y = 0.2 + 0.9

Combine like terms: 0.2 + 0.9 = 1.1
1.1y = 1.1

Divide each side by '1.1'.
y = 1

Simplifying
y = 1