0.3(y-4)=0.8(0.2y+2)

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Solution for 0.3(y-4)=0.8(0.2y+2) equation: 



0.3(y-4)=0.8(0.2y+2)

We move all terms to the left:

0.3(y-4)-(0.8(0.2y+2))=0

We multiply parentheses

0.3y-(0.8(0.2y+2))-1.2=0



We calculate terms in parentheses: -(0.8(0.2y+2)), so:

0.8(0.2y+2)

We multiply parentheses

0y+1.6

We add all the numbers together, and all the variables

y+1.6

Back to the equation:

-(y+1.6)



We get rid of parentheses

0.3y-y-1.6-1.2=0

We add all the numbers together, and all the variables

-0.7y-2.8=0

We move all terms containing y to the left, all other terms to the right

-0.7y=2.8

y=2.8/-0.7

y=-4

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