0.3+0.4(2-x)=6(-0.2+0.1x)+0.3

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Solution for 0.3+0.4(2-x)=6(-0.2+0.1x)+0.3 equation: 



0.3+0.4(2-x)=6(-0.2+0.1x)+0.3

We move all terms to the left:

0.3+0.4(2-x)-(6(-0.2+0.1x)+0.3)=0

We add all the numbers together, and all the variables

0.4(-1x+2)-(6(0.1x-0.2)+0.3)+0.3=0

We multiply parentheses

-0.4x-(6(0.1x-0.2)+0.3)+0.8+0.3=0



We calculate terms in parentheses: -(6(0.1x-0.2)+0.3), so:

6(0.1x-0.2)+0.3

We multiply parentheses

0x-1.2+0.3

We add all the numbers together, and all the variables

x-0.9

Back to the equation:

-(x-0.9)



We add all the numbers together, and all the variables

-0.4x-(x-0.9)+1.1=0

We get rid of parentheses

-0.4x-x+0.9+1.1=0

We add all the numbers together, and all the variables

-1.4x+2=0

We move all terms containing x to the left, all other terms to the right

-1.4x=-2

x=-2/-1.4

x=1+0.6/1.4

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