0.33(9x-6)+2x=4(x+3)-5

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Solution for 0.33(9x-6)+2x=4(x+3)-5 equation:



0.33(9x-6)+2x=4(x+3)-5
We move all terms to the left:
0.33(9x-6)+2x-(4(x+3)-5)=0
We add all the numbers together, and all the variables
2x+0.33(9x-6)-(4(x+3)-5)=0
We multiply parentheses
2x+2.97x-(4(x+3)-5)-1.98=0
We calculate terms in parentheses: -(4(x+3)-5), so:
4(x+3)-5
We multiply parentheses
4x+12-5
We add all the numbers together, and all the variables
4x+7
Back to the equation:
-(4x+7)
We add all the numbers together, and all the variables
4.97x-(4x+7)-1.98=0
We get rid of parentheses
4.97x-4x-7-1.98=0
We add all the numbers together, and all the variables
0.97x-8.98=0
We move all terms containing x to the left, all other terms to the right
0.97x=8.98
x=8.98/0.97
x=9+0.25/0.97

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