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0.35=35x^2
We move all terms to the left:
0.35-(35x^2)=0
a = -35; b = 0; c = +0.35;
Δ = b2-4ac
Δ = 02-4·(-35)·0.35
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-7}{2*-35}=\frac{-7}{-70} =1/10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+7}{2*-35}=\frac{7}{-70} =-1/10 $
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