0.36-0.81m2=0

Solution for 0.36-0.81m2=0 equation:

0.36-0.81m^2=0

a = -0.81; b = 0; c = +0.36;
Δ = b2-4ac
Δ = 02-4·(-0.81)·0.36
Δ = 1.1664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{1.1664}}{2*-0.81}=\frac{0-\sqrt{1.1664}}{-1.62}
=-\frac{\sqrt{}}{-1.62}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{1.1664}}{2*-0.81}=\frac{0+\sqrt{1.1664}}{-1.62}
=\frac{\sqrt{}}{-1.62}
$