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0.36h^2=0.36h
We move all terms to the left:
0.36h^2-(0.36h)=0
We add all the numbers together, and all the variables
0.36h^2-(+0.36h)=0
We get rid of parentheses
0.36h^2-0.36h=0
a = 0.36; b = -0.36; c = 0;
Δ = b2-4ac
Δ = -0.362-4·0.36·0
Δ = 0.1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.36)-\sqrt{0.1296}}{2*0.36}=\frac{0.36-\sqrt{0.1296}}{0.72} $$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.36)+\sqrt{0.1296}}{2*0.36}=\frac{0.36+\sqrt{0.1296}}{0.72} $
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