0.36x=(.01-x)(.01-x)

Solution for 0.36x=(.01-x)(.01-x) equation:

0.36x=(.01-x)(.01-x)

We move all terms to the left:

0.36x-((.01-x)(.01-x))=0

We add all the numbers together, and all the variables

0.36x-((-1x+0.01)(-1x+0.01))=0

We multiply parentheses ..

-((+x^2-0.01x-0.01x+0.0001))+0.36x=0


We calculate terms in parentheses: -((+x^2-0.01x-0.01x+0.0001)), so:

(+x^2-0.01x-0.01x+0.0001)

We get rid of parentheses

x^2-0.01x-0.01x+0.0001

We add all the numbers together, and all the variables

x^2-0.02x+0.0001

Back to the equation:

-(x^2-0.02x+0.0001)


We add all the numbers together, and all the variables

0.36x-(x^2-0.02x+0.0001)=0

We get rid of parentheses

-x^2+0.36x+0.02x-0.0001=0

We add all the numbers together, and all the variables

-1x^2+0.38x-0.0001=0

a = -1; b = 0.38; c = -0.0001;
Δ = b2-4ac
Δ = 0.382-4·(-1)·(-0.0001)
Δ = 0.144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.38)-\sqrt{0.144}}{2*-1}=\frac{-0.38-\sqrt{0.144}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.38)+\sqrt{0.144}}{2*-1}=\frac{-0.38+\sqrt{0.144}}{-2}
$