0.3f(0.2f-1.1)=3.804

Solution for 0.3f(0.2f-1.1)=3.804 equation:

0.3f(0.2f-1.1)=3.804

We move all terms to the left:

0.3f(0.2f-1.1)-(3.804)=0

We add all the numbers together, and all the variables

0.3f(0.2f-1.1)-3.804=0

We multiply parentheses

0f^2-0f-3.804=0

We add all the numbers together, and all the variables

f^2-1f-3.804=0

a = 1; b = -1; c = -3.804;
Δ = b2-4ac
Δ = -12-4·1·(-3.804)
Δ = 16.216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{16.216}}{2*1}=\frac{1-\sqrt{16.216}}{2}
$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{16.216}}{2*1}=\frac{1+\sqrt{16.216}}{2}
$