0.3x-0.2(20+x)=0.1(20)

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Solution for 0.3x-0.2(20+x)=0.1(20) equation:



0.3x-0.2(20+x)=0.1(20)
We move all terms to the left:
0.3x-0.2(20+x)-(0.1(20))=0
We add all the numbers together, and all the variables
0.3x-0.2(x+20)-(0.12)=0
We add all the numbers together, and all the variables
0.3x-0.2(x+20)-0.12=0
We multiply parentheses
0.3x-0.2x-4-0.12=0
We add all the numbers together, and all the variables
0.1x-4.12=0
We move all terms containing x to the left, all other terms to the right
0.1x=4.12
x=4.12/0.1
x=41+0.02/0.1

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