0.4(2-3x)=2(0.3x+0.4)-36

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Solution for 0.4(2-3x)=2(0.3x+0.4)-36 equation:



0.4(2-3x)=2(0.3x+0.4)-36
We move all terms to the left:
0.4(2-3x)-(2(0.3x+0.4)-36)=0
We add all the numbers together, and all the variables
0.4(-3x+2)-(2(0.3x+0.4)-36)=0
We multiply parentheses
-1.2x-(2(0.3x+0.4)-36)+0.8=0
We calculate terms in parentheses: -(2(0.3x+0.4)-36), so:
2(0.3x+0.4)-36
We multiply parentheses
0x+0.8-36
We add all the numbers together, and all the variables
x-35.2
Back to the equation:
-(x-35.2)
We get rid of parentheses
-1.2x-x+35.2+0.8=0
We add all the numbers together, and all the variables
-2.2x+36=0
We move all terms containing x to the left, all other terms to the right
-2.2x=-36
x=-36/-2.2
x=16+0.8/2.2

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