0.4(2-x)+0.6=0.2(x-2)

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Solution for 0.4(2-x)+0.6=0.2(x-2) equation: 



0.4(2-x)+0.6=0.2(x-2)

We move all terms to the left:

0.4(2-x)+0.6-(0.2(x-2))=0

We add all the numbers together, and all the variables

0.4(-1x+2)-(0.2(x-2))+0.6=0

We multiply parentheses

-0.4x-(0.2(x-2))+0.8+0.6=0



We calculate terms in parentheses: -(0.2(x-2)), so:

0.2(x-2)

We multiply parentheses

0.2x-0.4

Back to the equation:

-(0.2x-0.4)



We add all the numbers together, and all the variables

-0.4x-(0.2x-0.4)+1.4=0

We get rid of parentheses

-0.4x-0.2x+0.4+1.4=0

We add all the numbers together, and all the variables

-0.6x+1.8=0

We move all terms containing x to the left, all other terms to the right

-0.6x=-1.8

x=-1.8/-0.6

x=3+2.22044604925E-16/0.6

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