0.4(2x+1/2)=3(0.2x-1)-9

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Solution for 0.4(2x+1/2)=3(0.2x-1)-9 equation: 



0.4(2x+1/2)=3(0.2x-1)-9

We move all terms to the left:

0.4(2x+1/2)-(3(0.2x-1)-9)=0

We add all the numbers together, and all the variables

0.4(+2x+1/2)-(3(0.2x-1)-9)=0

We multiply parentheses

0.8x-(3(0.2x-1)-9)+1/2*0.4=0

We multiply all the terms by the denominator


(0.8x)*2*0.4-((3(0.2x-1)-9))*2*0.4+1=0

We add all the numbers together, and all the variables

(+0.8x)*2*0.4-((3(0.2x-1)-9))*2*0.4+1=0

We move all terms containing x to the left, all other terms to the right

(+0.8x)*2*0.4-((3(0.2x-1)-9))*2*0.4=-1

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