0.4+x=(0.2-x)(0.3-x)(20)

Solution for 0.4+x=(0.2-x)(0.3-x)(20) equation:

0.4+x=(0.2-x)(0.3-x)(20)

We move all terms to the left:

0.4+x-((0.2-x)(0.3-x)(20))=0

We add all the numbers together, and all the variables

x-((-1x+0.2)(-1x+0.3)20)+0.4=0

We multiply parentheses ..

-((+x^2-0.3x-0.2x+0.06)20)+x+0.4=0


We calculate terms in parentheses: -((+x^2-0.3x-0.2x+0.06)20), so:

(+x^2-0.3x-0.2x+0.06)20

We multiply parentheses

20x^2+0x+0x+1.2

We add all the numbers together, and all the variables

20x^2+2x+1.2

Back to the equation:

-(20x^2+2x+1.2)


We add all the numbers together, and all the variables

x-(20x^2+2x+1.2)+0.4=0

We get rid of parentheses

-20x^2+x-2x-1.2+0.4=0

We add all the numbers together, and all the variables

-20x^2-1x-0.8=0

a = -20; b = -1; c = -0.8;
Δ = b2-4ac
Δ = -12-4·(-20)·(-0.8)
Δ = -63
Delta is less than zero, so there is no solution for the equation