0.4x(x-2)+0.5=1-0.1(4-2x)-0.5

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Solution for 0.4x(x-2)+0.5=1-0.1(4-2x)-0.5 equation: 



0.4x(x-2)+0.5=1-0.1(4-2x)-0.5

We move all terms to the left:

0.4x(x-2)+0.5-(1-0.1(4-2x)-0.5)=0

We add all the numbers together, and all the variables

0.4x(x-2)-(1-0.1(-2x+4)-0.5)+0.5=0

We multiply parentheses

0x^2+0x-(1-0.1(-2x+4)-0.5)+0.5=0



We calculate terms in parentheses: -(1-0.1(-2x+4)-0.5), so:

1-0.1(-2x+4)-0.5

determiningTheFunctionDomain
-0.1(-2x+4)+1-0.5

We add all the numbers together, and all the variables

-0.1(-2x+4)+0.5

We multiply parentheses

0.2x-0.4+0.5

We add all the numbers together, and all the variables

0.2x+0.1

Back to the equation:

-(0.2x+0.1)



We add all the numbers together, and all the variables

x^2+x-(0.2x+0.1)+0.5=0

We get rid of parentheses

x^2+x-0.2x-0.1+0.5=0

We add all the numbers together, and all the variables

x^2+0.8x+0.4=0

a = 1; b = 0.8; c = +0.4;
Δ = b2-4ac
Δ = 0.82-4·1·0.4
Δ = -0.96
Delta is less than zero, so there is no solution for the equation

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