0.4x+0.05(12-x)=0.10(22)

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Solution for 0.4x+0.05(12-x)=0.10(22) equation:



0.4x+0.05(12-x)=0.10(22)
We move all terms to the left:
0.4x+0.05(12-x)-(0.10(22))=0
We add all the numbers together, and all the variables
0.4x+0.05(-1x+12)-(0.1022)=0
We add all the numbers together, and all the variables
0.4x+0.05(-1x+12)-0.1022=0
We multiply parentheses
0.4x-0.05x+0.6-0.1022=0
We add all the numbers together, and all the variables
0.35x+0.4978=0
We move all terms containing x to the left, all other terms to the right
0.35x=-0.4978
x=-0.4978/0.35
x=-1+0.1478/0.35

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