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0.4x+3=-1/3x-5
We move all terms to the left:
0.4x+3-(-1/3x-5)=0
Domain of the equation: 3x-5)!=0We get rid of parentheses
x∈R
0.4x+1/3x+5+3=0
We multiply all the terms by the denominator
(0.4x)*3x+5*3x+3*3x+1=0
We add all the numbers together, and all the variables
(+0.4x)*3x+5*3x+3*3x+1=0
We multiply parentheses
0x^2+5*3x+3*3x+1=0
Wy multiply elements
0x^2+15x+9x+1=0
We add all the numbers together, and all the variables
x^2+24x+1=0
a = 1; b = 24; c = +1;
Δ = b2-4ac
Δ = 242-4·1·1
Δ = 572
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{572}=\sqrt{4*143}=\sqrt{4}*\sqrt{143}=2\sqrt{143}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-2\sqrt{143}}{2*1}=\frac{-24-2\sqrt{143}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+2\sqrt{143}}{2*1}=\frac{-24+2\sqrt{143}}{2} $
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