0.4x-0.1(13-3x)=-0.8(x-4)

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Solution for 0.4x-0.1(13-3x)=-0.8(x-4) equation: 



0.4x-0.1(13-3x)=-0.8(x-4)

We move all terms to the left:

0.4x-0.1(13-3x)-(-0.8(x-4))=0

We add all the numbers together, and all the variables

0.4x-0.1(-3x+13)-(-0.8(x-4))=0

We multiply parentheses

0.4x+0.3x-(-0.8(x-4))-1.3=0



We calculate terms in parentheses: -(-0.8(x-4)), so:

-0.8(x-4)

We multiply parentheses

-0.8x+3.2

Back to the equation:

-(-0.8x+3.2)



We add all the numbers together, and all the variables

0.7x-(-0.8x+3.2)-1.3=0

We get rid of parentheses

0.7x+0.8x-3.2-1.3=0

We add all the numbers together, and all the variables

1.5x-4.5=0

We move all terms containing x to the left, all other terms to the right

1.5x=4.5

x=4.5/1.5

x=3

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