0.5(-12c+6)-3(c+4)+10(c-5)=

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Solution for 0.5(-12c+6)-3(c+4)+10(c-5)= equation:


0.5(-12c+6)-3(c+4)+10(c-5)=0

We simplify the equation to the form, which is simple to understand 
0.5(-12c+6)-3(c+4)+10(c-5)=0

Reorder the terms in parentheses
+(-6c+3)-3*(c+4)+10*(c-5)=0

Remove unnecessary parentheses
-6c+3-3+*(+c+4+)+10+*(+c-5+)=0

Reorder the terms in parentheses
-6c+3+(-3c-12)+10*(c-5)=0

Remove unnecessary parentheses
-6c+3-3c-12+10+*(+c-5+)=0

Reorder the terms in parentheses
-6c+3-3c-12+(+10c-50)=0

Remove unnecessary parentheses
-6c+3-3c-12+10c-50=0

We move all terms containing c to the left and all other terms to the right. 
-6c-3c+10c=0-3+12+50

We simplify left and right side of the equation. 
+1c=+59

We divide both sides of the equation by 1 to get c. 
c=59

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