0.5(-12c+6)=-3(c+4)+10(c-50)

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Solution for 0.5(-12c+6)=-3(c+4)+10(c-50) equation: 



0.5(-12c+6)=-3(c+4)+10(c-50)

We move all terms to the left:

0.5(-12c+6)-(-3(c+4)+10(c-50))=0

We multiply parentheses

-6c-(-3(c+4)+10(c-50))+3=0



We calculate terms in parentheses: -(-3(c+4)+10(c-50)), so:

-3(c+4)+10(c-50)

We multiply parentheses

-3c+10c-12-500

We add all the numbers together, and all the variables

7c-512

Back to the equation:

-(7c-512)



We get rid of parentheses

-6c-7c+512+3=0

We add all the numbers together, and all the variables

-13c+515=0

We move all terms containing c to the left, all other terms to the right

-13c=-515

c=-515/-13

c=39+8/13

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