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0.5(10x-4)-5(x-1)=3(2x+1)-2x
We move all terms to the left:
0.5(10x-4)-5(x-1)-(3(2x+1)-2x)=0
We multiply parentheses
5x-5x-(3(2x+1)-2x)-2+5=0
We calculate terms in parentheses: -(3(2x+1)-2x), so:We add all the numbers together, and all the variables
3(2x+1)-2x
We add all the numbers together, and all the variables
-2x+3(2x+1)
We multiply parentheses
-2x+6x+3
We add all the numbers together, and all the variables
4x+3
Back to the equation:
-(4x+3)
-(4x+3)+3=0
We get rid of parentheses
-4x-3+3=0
We add all the numbers together, and all the variables
-4x=0
x=0/-4
x=0
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