0.5(12-16x)=8-(4x+6)

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Solution for 0.5(12-16x)=8-(4x+6) equation: 



0.5(12-16x)=8-(4x+6)

We move all terms to the left:

0.5(12-16x)-(8-(4x+6))=0

We add all the numbers together, and all the variables

0.5(-16x+12)-(8-(4x+6))=0

We multiply parentheses

-8x-(8-(4x+6))+6=0



We calculate terms in parentheses: -(8-(4x+6)), so:

8-(4x+6)

determiningTheFunctionDomain
-(4x+6)+8

We get rid of parentheses

-4x-6+8

We add all the numbers together, and all the variables

-4x+2

Back to the equation:

-(-4x+2)



We get rid of parentheses

-8x+4x-2+6=0

We add all the numbers together, and all the variables

-4x+4=0

We move all terms containing x to the left, all other terms to the right

-4x=-4

x=-4/-4

x=1

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