0.5(12x-6)=(-3x+3/2)

Solution for 0.5(12x-6)=(-3x+3/2) equation:

0.5(12x-6)=(-3x+3/2)

We move all terms to the left:

0.5(12x-6)-((-3x+3/2))=0

We multiply parentheses

6x-((-3x+3/2))-3=0

We multiply all the terms by the denominator


6x*2))-((-3x+3-3*2))=0

We add all the numbers together, and all the variables

6x*2))-((-3x-3))=0

We add all the numbers together, and all the variables

-3x+6x*2))-((=0

Wy multiply elements

12x^2-3x=0

a = 12; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·12·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*12}=\frac{0}{24}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*12}=\frac{6}{24}
=1/4
$