0.5(2x-4)+2=4(x+2)-11

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Solution for 0.5(2x-4)+2=4(x+2)-11 equation:



0.5(2x-4)+2=4(x+2)-11
We move all terms to the left:
0.5(2x-4)+2-(4(x+2)-11)=0
We multiply parentheses
x-(4(x+2)-11)-2+2=0
We calculate terms in parentheses: -(4(x+2)-11), so:
4(x+2)-11
We multiply parentheses
4x+8-11
We add all the numbers together, and all the variables
4x-3
Back to the equation:
-(4x-3)
We add all the numbers together, and all the variables
x-(4x-3)=0
We get rid of parentheses
x-4x+3=0
We add all the numbers together, and all the variables
-3x+3=0
We move all terms containing x to the left, all other terms to the right
-3x=-3
x=-3/-3
x=1

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