0.5(3x+5)-0.1(12+x-5)=2(1+0.1x)

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Solution for 0.5(3x+5)-0.1(12+x-5)=2(1+0.1x) equation: 



0.5(3x+5)-0.1(12+x-5)=2(1+0.1x)

We move all terms to the left:

0.5(3x+5)-0.1(12+x-5)-(2(1+0.1x))=0

We add all the numbers together, and all the variables

0.5(3x+5)-0.1(x+7)-(2(0.1x+1))=0

We multiply parentheses

1.5x-0.1x-(2(0.1x+1))+2.5-0.7=0



We calculate terms in parentheses: -(2(0.1x+1)), so:

2(0.1x+1)

We multiply parentheses

0x+2

We add all the numbers together, and all the variables

x+2

Back to the equation:

-(x+2)



We add all the numbers together, and all the variables

1.4x-(x+2)+1.8=0

We get rid of parentheses

1.4x-x-2+1.8=0

We add all the numbers together, and all the variables

0.4x-0.2=0

We move all terms containing x to the left, all other terms to the right

0.4x=0.2

x=0.2/0.4

x=0.2/0.4

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