0.5(3x+5)-0.1(12x-5)=3(1+0,1x)

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Solution for 0.5(3x+5)-0.1(12x-5)=3(1+0,1x) equation:



0.5(3x+5)-0.1(12x-5)=3(1+0.1x)
We move all terms to the left:
0.5(3x+5)-0.1(12x-5)-(3(1+0.1x))=0
We add all the numbers together, and all the variables
0.5(3x+5)-0.1(12x-5)-(3(0.1x+1))=0
We multiply parentheses
1.5x-1.2x-(3(0.1x+1))+2.5+0.5=0
We calculate terms in parentheses: -(3(0.1x+1)), so:
3(0.1x+1)
We multiply parentheses
0x+3
We add all the numbers together, and all the variables
x+3
Back to the equation:
-(x+3)
We add all the numbers together, and all the variables
0.3x-(x+3)+3=0
We get rid of parentheses
0.3x-x-3+3=0
We add all the numbers together, and all the variables
-0.7x=0
x=0/-0.7
x=0

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