0.5(4r-12)=7-(4r-3)

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Solution for 0.5(4r-12)=7-(4r-3) equation:



0.5(4r-12)=7-(4r-3)
We move all terms to the left:
0.5(4r-12)-(7-(4r-3))=0
We multiply parentheses
2r-(7-(4r-3))-6=0
We calculate terms in parentheses: -(7-(4r-3)), so:
7-(4r-3)
determiningTheFunctionDomain -(4r-3)+7
We get rid of parentheses
-4r+3+7
We add all the numbers together, and all the variables
-4r+10
Back to the equation:
-(-4r+10)
We get rid of parentheses
2r+4r-10-6=0
We add all the numbers together, and all the variables
6r-16=0
We move all terms containing r to the left, all other terms to the right
6r=16
r=16/6
r=2+2/3

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