0.5(4r-12)=7-(4r-3)

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Solution for 0.5(4r-12)=7-(4r-3) equation: 



0.5(4r-12)=7-(4r-3)

We move all terms to the left:

0.5(4r-12)-(7-(4r-3))=0

We multiply parentheses

2r-(7-(4r-3))-6=0



We calculate terms in parentheses: -(7-(4r-3)), so:

7-(4r-3)

determiningTheFunctionDomain
-(4r-3)+7

We get rid of parentheses

-4r+3+7

We add all the numbers together, and all the variables

-4r+10

Back to the equation:

-(-4r+10)



We get rid of parentheses

2r+4r-10-6=0

We add all the numbers together, and all the variables

6r-16=0

We move all terms containing r to the left, all other terms to the right

6r=16

r=16/6

r=2+2/3

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