0.5(4x+2)-0.1(8x-12)=4(1+0.5x)

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Solution for 0.5(4x+2)-0.1(8x-12)=4(1+0.5x) equation:



0.5(4x+2)-0.1(8x-12)=4(1+0.5x)
We move all terms to the left:
0.5(4x+2)-0.1(8x-12)-(4(1+0.5x))=0
We add all the numbers together, and all the variables
0.5(4x+2)-0.1(8x-12)-(4(0.5x+1))=0
We multiply parentheses
2x-0.8x-(4(0.5x+1))+1+1.2=0
We calculate terms in parentheses: -(4(0.5x+1)), so:
4(0.5x+1)
We multiply parentheses
0x+4
We add all the numbers together, and all the variables
x+4
Back to the equation:
-(x+4)
We add all the numbers together, and all the variables
1.2x-(x+4)+2.2=0
We get rid of parentheses
1.2x-x-4+2.2=0
We add all the numbers together, and all the variables
0.2x-1.8=0
We move all terms containing x to the left, all other terms to the right
0.2x=1.8
x=1.8/0.2
x=9

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