0.5(4x+2)=4(1x-3)

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Solution for 0.5(4x+2)=4(1x-3) equation: 



0.5(4x+2)=4(1x-3)

We move all terms to the left:

0.5(4x+2)-(4(1x-3))=0

We add all the numbers together, and all the variables

0.5(4x+2)-(4(x-3))=0

We multiply parentheses

2x-(4(x-3))+1=0



We calculate terms in parentheses: -(4(x-3)), so:

4(x-3)

We multiply parentheses

4x-12

Back to the equation:

-(4x-12)



We get rid of parentheses

2x-4x+12+1=0

We add all the numbers together, and all the variables

-2x+13=0

We move all terms containing x to the left, all other terms to the right

-2x=-13

x=-13/-2

x=6+1/2

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