0.5(4x+5)=9x-12(1x-1)

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Solution for 0.5(4x+5)=9x-12(1x-1) equation: 



0.5(4x+5)=9x-12(1x-1)

We move all terms to the left:

0.5(4x+5)-(9x-12(1x-1))=0

We add all the numbers together, and all the variables

0.5(4x+5)-(9x-12(x-1))=0

We multiply parentheses

2x-(9x-12(x-1))+2.5=0



We calculate terms in parentheses: -(9x-12(x-1)), so:

9x-12(x-1)

We multiply parentheses

9x-12x+12

We add all the numbers together, and all the variables

-3x+12

Back to the equation:

-(-3x+12)



We get rid of parentheses

2x+3x-12+2.5=0

We add all the numbers together, and all the variables

5x-9.5=0

We move all terms containing x to the left, all other terms to the right

5x=9.5

x=9.5/5

x=1+3/3.3333333333333

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