0.5(4x-6)+0.3(3-9x)=-0.4(10x-15)-11

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Solution for 0.5(4x-6)+0.3(3-9x)=-0.4(10x-15)-11 equation:



0.5(4x-6)+0.3(3-9x)=-0.4(10x-15)-11
We move all terms to the left:
0.5(4x-6)+0.3(3-9x)-(-0.4(10x-15)-11)=0
We add all the numbers together, and all the variables
0.5(4x-6)+0.3(-9x+3)-(-0.4(10x-15)-11)=0
We multiply parentheses
2x-2.7x-(-0.4(10x-15)-11)-3+0.9=0
We calculate terms in parentheses: -(-0.4(10x-15)-11), so:
-0.4(10x-15)-11
We multiply parentheses
-4x+6-11
We add all the numbers together, and all the variables
-4x-5
Back to the equation:
-(-4x-5)
We add all the numbers together, and all the variables
-0.7x-(-4x-5)-2.1=0
We get rid of parentheses
-0.7x+4x+5-2.1=0
We add all the numbers together, and all the variables
3.3x+2.9=0
We move all terms containing x to the left, all other terms to the right
3.3x=-2.9
x=-2.9/3.3
x=-2.9/3.3

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