0.5(4x-6)+0.3(3-9x)=-0.4(10x-15)-11

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Solution for 0.5(4x-6)+0.3(3-9x)=-0.4(10x-15)-11 equation: 



0.5(4x-6)+0.3(3-9x)=-0.4(10x-15)-11

We move all terms to the left:

0.5(4x-6)+0.3(3-9x)-(-0.4(10x-15)-11)=0

We add all the numbers together, and all the variables

0.5(4x-6)+0.3(-9x+3)-(-0.4(10x-15)-11)=0

We multiply parentheses

2x-2.7x-(-0.4(10x-15)-11)-3+0.9=0



We calculate terms in parentheses: -(-0.4(10x-15)-11), so:

-0.4(10x-15)-11

We multiply parentheses

-4x+6-11

We add all the numbers together, and all the variables

-4x-5

Back to the equation:

-(-4x-5)



We add all the numbers together, and all the variables

-0.7x-(-4x-5)-2.1=0

We get rid of parentheses

-0.7x+4x+5-2.1=0

We add all the numbers together, and all the variables

3.3x+2.9=0

We move all terms containing x to the left, all other terms to the right

3.3x=-2.9

x=-2.9/3.3

x=-2.9/3.3

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