0.5(f+4)=2/10(f+4)

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Solution for 0.5(f+4)=2/10(f+4) equation: 



0.5(f+4)=2/10(f+4)

We move all terms to the left:

0.5(f+4)-(2/10(f+4))=0



Domain of the equation: 10(f+4))!=0

f∈R



We multiply parentheses

0.5f-(2/10(f+4))+2=0

We multiply all the terms by the denominator


(0.5f)*10(f+4))-(2+2*10(f+4))=0

We add all the numbers together, and all the variables

(+0.5f)*10(f+4))-(2+2*10(f+4))=0

Wy multiply elements

(+0.5f)*10(f+4))-(2+20f(f=0

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