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0.5(x-7)-2/5(2x+5)=2
We move all terms to the left:
0.5(x-7)-2/5(2x+5)-(2)=0
Domain of the equation: 5(2x+5)!=0We multiply parentheses
x∈R
0.5x-2/5(2x+5)-3.5-2=0
We multiply all the terms by the denominator
(0.5x)*5(2x+5)-(3.5)*5(2x+5)-2*5(2x+5)-2=0
We add all the numbers together, and all the variables
(+0.5x)*5(2x+5)-(3.5)*5(2x+5)-2*5(2x+5)-2=0
Wy multiply elements
(+0.5x)*5(2x+5)-(3.5)*5(2x+5)-10x(2-2=0
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