0.5(y+1)=1.5(1+2y)-3

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Solution for 0.5(y+1)=1.5(1+2y)-3 equation: 



0.5(y+1)=1.5(1+2y)-3

We move all terms to the left:

0.5(y+1)-(1.5(1+2y)-3)=0

We add all the numbers together, and all the variables

0.5(y+1)-(1.5(2y+1)-3)=0

We multiply parentheses

0.5y-(1.5(2y+1)-3)+0.5=0



We calculate terms in parentheses: -(1.5(2y+1)-3), so:

1.5(2y+1)-3

We multiply parentheses

3y+1.5-3

We add all the numbers together, and all the variables

3y-1.5

Back to the equation:

-(3y-1.5)



We get rid of parentheses

0.5y-3y+1.5+0.5=0

We add all the numbers together, and all the variables

-2.5y+2=0

We move all terms containing y to the left, all other terms to the right

-2.5y=-2

y=-2/-2.5

y=1/1.25

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