0.50(8x-10)+x+8=-x+3(9-2x)-(x-2)

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Solution for 0.50(8x-10)+x+8=-x+3(9-2x)-(x-2) equation:



0.50(8x-10)+x+8=-x+3(9-2x)-(x-2)
We move all terms to the left:
0.50(8x-10)+x+8-(-x+3(9-2x)-(x-2))=0
We add all the numbers together, and all the variables
0.50(8x-10)+x-(-x+3(-2x+9)-(x-2))+8=0
We add all the numbers together, and all the variables
x+0.50(8x-10)-(-x+3(-2x+9)-(x-2))+8=0
We multiply parentheses
x+4x-(-x+3(-2x+9)-(x-2))-5+8=0
We calculate terms in parentheses: -(-x+3(-2x+9)-(x-2)), so:
-x+3(-2x+9)-(x-2)
We add all the numbers together, and all the variables
-1x+3(-2x+9)-(x-2)
We multiply parentheses
-1x-6x-(x-2)+27
We get rid of parentheses
-1x-6x-x+2+27
We add all the numbers together, and all the variables
-8x+29
Back to the equation:
-(-8x+29)
We add all the numbers together, and all the variables
5x-(-8x+29)+3=0
We get rid of parentheses
5x+8x-29+3=0
We add all the numbers together, and all the variables
13x-26=0
We move all terms containing x to the left, all other terms to the right
13x=26
x=26/13
x=2

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