0.55x+0.5(4-x)=10(42)

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Solution for 0.55x+0.5(4-x)=10(42) equation: 



0.55x+0.5(4-x)=10(42)

We move all terms to the left:

0.55x+0.5(4-x)-(10(42))=0

determiningTheFunctionDomain
0.55x+0.5(4-x)-1042=0

We add all the numbers together, and all the variables

0.55x+0.5(-1x+4)-1042=0

We multiply parentheses

0.55x-0.5x+2-1042=0

We add all the numbers together, and all the variables

0.05x-1040=0

We move all terms containing x to the left, all other terms to the right

0.05x=1040

x=1040/0.05

x=20800

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